Az SQL csatlakozások lehetővé teszik, hogy relációs adatbázis-kezelő rendszereink relatívak legyenek.
A csatlakozások lehetővé teszik számunkra, hogy az elválasztott adatbázis-táblákat visszakonstruáljuk az alkalmazásokat működtető kapcsolatokba.
Ebben a cikkben megvizsgáljuk az SQL egyesülési típusait és azok használatát.
A következőket ismertetjük:
- Mi a csatlakozás?
- Az adatbázis beállítása
CROSS JOIN- Példaadataink (rendezők és filmek) beállítása
FULL OUTER JOININNER JOINLEFT JOIN/RIGHT JOIN- Szűrés a következővel:
LEFT JOIN - Többszörös csatlakozás
- Csatlakozik extra feltételekkel
- A lekérdezések írása a csatlakozásokkal
( Spoiler riasztás : öt különféle típust tárgyalunk - de valójában csak kettőt kell ismernie!)
Mi a csatlakozás?
Az összekapcsolás olyan művelet, amely két sort egyesít egy sorba.
Ezek a sorok általában két különböző táblából származnak - de nem feltétlenül.
Mielőtt megvizsgálnánk, hogyan kell írni a csatlakozást, nézzük meg, hogy nézne ki egy összekapcsolás eredménye.
Vegyünk például egy rendszert, amely információkat tárol a felhasználókról és azok címeiről.
A felhasználói adatokat tároló táblázat sorai így nézhetnek ki:
id | name | email | age ----+--------------+---------------------+----- 1 | John Smith | [email protected] | 25 2 | Jane Doe | [email protected] | 28 3 | Xavier Wills | [email protected] | 3 ... (7 rows)És a táblázat címadatokat tároló sorai így nézhetnek ki:
id | street | city | state | user_id ----+-------------------+---------------+-------+--------- 1 | 1234 Main Street | Oklahoma City | OK | 1 2 | 4444 Broadway Ave | Oklahoma City | OK | 2 3 | 5678 Party Ln | Tulsa | OK | 3 (3 rows)Külön lekérdezéseket írhatnánk mind a felhasználói, mind a címadatok lekérésére - ideális esetben azonban egy lekérdezést írhatnánk, és az összes felhasználót és címüket ugyanabban az eredményhalmazban fogadnánk.
A csatlakozás pontosan ezt teszi lehetővé!
Hamarosan megvizsgáljuk, hogyan írhatjuk ezeket a csatlakozásokat, de ha felhasználói adatainkat összekapcsolnánk a címadatainkkal, akkor egy ilyen eredményt kaphatnánk:
id | name | email | age | id | street | city | state | user_id ----+--------------+---------------------+-----+----+-------------------+---------------+-------+--------- 1 | John Smith | [email protected] | 25 | 1 | 1234 Main Street | Oklahoma City | OK | 1 2 | Jane Doe | [email protected] | 28 | 2 | 4444 Broadway Ave | Oklahoma City | OK | 2 3 | Xavier Wills | xav[email protected] | 35 | 3 | 5678 Party Ln | Tulsa | OK | 3 (3 rows) Itt minden felhasználónkat és címüket egy szép eredménysorban láthatjuk.
A kombinált eredménykészlet mellett a csatlakozások másik fontos felhasználása az, hogy további információkat vonzunk be a lekérdezésbe, amelyek alapján szűrni tudjuk.
Például, ha valamilyen fizikai levelet szeretnénk küldeni az összes felhasználónak, aki Oklahoma Cityben él, akkor ezt az összekapcsolt eredménykészletet és szűrőt használhatjuk az cityoszlop alapján.
Most, hogy tudjuk a csatlakozások célját - kezdjünk el írni néhányat!
Az adatbázis beállítása
Mielőtt megírhatnánk kérdéseinket, be kell állítanunk az adatbázisunkat.
Ezekhez a példákhoz a PostgreSQL-t fogjuk használni, de az itt bemutatott lekérdezések és fogalmak könnyen lefordíthatók bármely más modern adatbázis-rendszerbe (például MySQL, SQL Server stb.).
A PostgreSQL adatbázisunk használatához használhatjuk az psqlinteraktív PostgreSQL parancssori programot. Ha van még egy adatbázis-kliensed, akivel szívesen dolgozol, az is rendben van.
Először hozzuk létre az adatbázisunkat. Ha a PostgreSQL már telepítve van createdb , a terminálunkon futtathatjuk a parancsot egy új adatbázis létrehozásához. Felhívtam az enyémet fcc:
$ createdb fcc Ezután indítsuk el az interaktív konzolt a parancs használatával, psqlés csatlakozzunk az imént létrehozott adatbázishoz \c :
$ psql psql (11.5) Type "help" for help. john=# \c fcc You are now connected to database "fcc" as user "john". fcc=# psql példák kimenetét megtisztítottam
az olvasás megkönnyítése érdekében, ezért ne aggódjon, ha az itt bemutatott kimenet nem pontosan az, amit a terminálján látott.
Javaslom, hogy kövesse ezeket a példákat, és futtassa le ezeket a kérdéseket saját maga számára. Sokkal többet fog megtudni és emlékezni azáltal, hogy átdolgozza ezeket a példákat, nem csak elolvassa őket.
Most a csatlakozásokra!
CROSS JOIN
A legegyszerűbb típusú csatlakozás, amelyet tehetünk, egy CROSS JOINvagy "derékszögű termék".
Ez a csatlakozás elveszi az egyik tábla minden sorát, és összekapcsolja a másik tábla minden sorával.
Ha két listánk lenne - az egyik tartalmazza 1, 2, 3, a másik pedig tartalmazza A, B, C-, akkor e két lista derékszögű szorzata a következő lenne:
1A, 1B, 1C 2A, 2B, 2C 3A, 3B, 3C Az első lista minden értéke párosul a második lista minden értékével.
Let's write this same example as a SQL query.
First let's create two very simple tables and insert some data into them:
CREATE TABLE letters( letter TEXT ); INSERT INTO letters(letter) VALUES ('A'), ('B'), ('C'); CREATE TABLE numbers( number TEXT ); INSERT INTO numbers(number) VALUES (1), (2), (3); Our two tables, letters and numbers, just have one column: a simple text field.
Now let's join them together with a CROSS JOIN:
SELECT * FROM letters CROSS JOIN numbers; letter | number --------+-------- A | 1 A | 2 A | 3 B | 1 B | 2 B | 3 C | 1 C | 2 C | 3 (9 rows) This is the simplest type of join we can do—but even in this simple example we can see the join at work: the two separate rows (one from letters and one from numbers) have been joined together to form one row.
While this type of join is often discussed as a mere academic example, it does have at least one good use case: covering date ranges.
CROSS JOIN with date ranges
One good use case of a CROSS JOIN is to take each row from a table and apply it to every day within a date range.
Say for example you were building an application that tracked daily tasks—things like brushing your teeth, eating breakfast, or showering.
If you wanted to generate a record for every task and for each day of the past week, you could use a CROSS JOIN against a date range.
To make this date range, we can use the generate_series function:
SELECT generate_series( (CURRENT_DATE - INTERVAL '5 day'), CURRENT_DATE, INTERVAL '1 day' )::DATE AS day; The generate_series function takes three parameters.
The first parameter is the starting value. In this example we use CURRENT_DATE - INTERVAL '5 day'. This returns the current date minus five days—or "five days ago."
The second parameter is the current date (CURRENT_DATE).
The third parameter is the "step interval"—or how much we want to increment the value each time. Since these are daily tasks we'll use the interval of one day (INTERVAL '1 day').
Putting it all together, this generates a series of dates starting five days ago, ending today, and going one day at a time.
Finally we remove the time portion by casting the output of these values to a date using ::DATE, and we alias this column using AS day to make the output a little nicer.
The output of this query is the past five days plus today:
day ------------ 2020-08-19 2020-08-20 2020-08-21 2020-08-22 2020-08-23 2020-08-24 (6 rows) Going back to our tasks-per-day example, let's create a simple table to hold the tasks we want to complete and insert a few tasks:
CREATE TABLE tasks( name TEXT ); INSERT INTO tasks(name) VALUES ('Brush teeth'), ('Eat breakfast'), ('Shower'), ('Get dressed'); Our tasks table just has one column, name, and we inserted four tasks into this table.
Now let's CROSS JOIN our tasks with the query to generate the dates:
SELECT tasks.name, dates.day FROM tasks CROSS JOIN ( SELECT generate_series( (CURRENT_DATE - INTERVAL '5 day'), CURRENT_DATE, INTERVAL '1 day' )::DATE AS day ) AS dates (Since our date generation query is not an actual table we just write it as a subquery.)
From this query we return the task name and the day, and the result set looks like this:
name | day ---------------+------------ Brush teeth | 2020-08-19 Brush teeth | 2020-08-20 Brush teeth | 2020-08-21 Brush teeth | 2020-08-22 Brush teeth | 2020-08-23 Brush teeth | 2020-08-24 Eat breakfast | 2020-08-19 Eat breakfast | 2020-08-20 Eat breakfast | 2020-08-21 Eat breakfast | 2020-08-22 ... (24 rows) Like we expected, we get a row for each task for every day in our date range.
The CROSS JOIN is the simplest join we can do, but to look at the next few types we'll need a more-realistic table setup.
Creating directors and movies
To illustrate the following join types, we'll use the example of movies and movie directors.
In this situation, a movie has one director, but a movie isn't required to have a director—imagine a new movie being announced but the choice for director hasn't yet been confirmed.
Our directors table will store the name of each director, and the movies table will store the name of the movie as well as a reference to the director of the movie (if it has one).
Let's create those two tables and insert some data into them:
CREATE TABLE directors( id SERIAL PRIMARY KEY, name TEXT NOT NULL ); INSERT INTO directors(name) VALUES ('John Smith'), ('Jane Doe'), ('Xavier Wills') ('Bev Scott'), ('Bree Jensen'); CREATE TABLE movies( id SERIAL PRIMARY KEY, name TEXT NOT NULL, director_id INTEGER REFERENCES directors ); INSERT INTO movies(name, director_id) VALUES ('Movie 1', 1), ('Movie 2', 1), ('Movie 3', 2), ('Movie 4', NULL), ('Movie 5', NULL); We have five directors, five movies, and three of those movies have directors assigned to them. Director ID 1 has two movies, and director ID 2 has one.
FULL OUTER JOIN
Now that we have some data to work with let's look at the FULL OUTER JOIN.
A FULL OUTER JOIN has some similarities to a CROSS JOIN, but it has a couple key differences.
The first difference is that a FULL OUTER JOIN requires a join condition.
A join condition specifies how the rows between the two tables are related to each other and on what criteria they should be joined together.
In our example, our movies table has a reference to the director via the director_id column, and this column matches the id column of the directors table. These are the two columns that we will use as our join condition.
Here's how we write this join between our two tables:
SELECT * FROM movies FULL OUTER JOIN directors ON directors.id = movies.director_id; Notice the join condition we specified that matches the movie to its director: ON movies.director_id = directors.id.
Our result set looks like an odd Cartesian product of sorts:
id | name | director_id | id | name ------+---------+-------------+------+-------------- 1 | Movie 1 | 1 | 1 | John Smith 2 | Movie 2 | 1 | 1 | John Smith 3 | Movie 3 | 2 | 2 | Jane Doe 4 | Movie 4 | NULL | NULL | NULL 5 | Movie 5 | NULL | NULL | NULL NULL | NULL | NULL | 5 | Bree Jensen NULL | NULL | NULL | 4 | Bev Scott NULL | NULL | NULL | 3 | Xavier Wills (8 rows) The first rows we see are ones where the movie had a director, and our join condition evaluated to true.
Azonban ezek után a sorok után megnézzük az egyes táblák megmaradt sorait - de olyan NULLértékekkel, ahol a másik asztalnak nem volt egyezése.
NULLértékeket, olvassa el itt a magyarázatomat ebben az SQL operátor oktatóanyagban.
Egy másik különbséget is látunk a CROSS JOINés FULL OUTER JOINitt között. A FULL OUTER JOINminden táblázatból egy külön sort ad vissza - ellentétben azzal CROSS JOIN, amelyiknek több van.
INNER JOIN
A következő csatlakozási típus, INNER JOINaz egyik leggyakrabban használt csatlakozási típus.
A belső illesztés csak akkor ad vissza sorokat, ha a csatlakozás feltétele igaz.
Példánkban egy belső csatlakozzon a mi moviesés a directorstáblázatok csak visszatér rekordokat, ahol a film lett hozzárendelve a rendező.
The syntax is basically the same as before:
SELECT * FROM movies INNER JOIN directors ON directors.id = movies.director_id; Our result shows the three movies that have a director:
id | name | director_id | id | name ----+---------+-------------+----+------------ 1 | Movie 1 | 1 | 1 | John Smith 2 | Movie 2 | 1 | 1 | John Smith 3 | Movie 3 | 2 | 2 | Jane Doe (3 rows) Since an inner join only includes rows that match the join condition, the order of the two tables in the join don't matter.
If we reverse the order of the tables in the query we get same result:
SELECT * FROM directors INNER JOIN movies ON movies.director_id = directors.id; id | name | id | name | director_id ----+------------+----+---------+------------- 1 | John Smith | 1 | Movie 1 | 1 1 | John Smith | 2 | Movie 2 | 1 2 | Jane Doe | 3 | Movie 3 | 2 (3 rows) Since we listed the directors table first in this query and we selected all columns (SELECT *), we see the directors column data first and then the columns from movies—but the resulting data is the same.
This is a useful property of inner joins, but it's not true for all join types—like our next type.
LEFT JOIN / RIGHT JOIN
These next two join types use a modifier (LEFT or RIGHT) that affects which table's data is included in the result set.
LEFT JOINés
RIGHT JOINnevezhetjük
LEFT OUTER JOINés
RIGHT OUTER JOIN.
Ezeket az összekapcsolásokat olyan lekérdezésekben használják, ahol vissza akarjuk adni az adott tábla összes adatait, és ha vannak ilyenek, akkor a társított tábla adatait is.
Ha a társított adatok nem léteznek, akkor is visszakapjuk az "elsődleges" táblázat összes adatait.
Ez egy adott dologra és bónusz információkra vonatkozó lekérdezés, ha ezek a bónusz információk léteznek.
Ezt egyszerű lesz megérteni egy példával. Keressünk meg minden filmet és rendezőt, de nem érdekel, van-e rendezőjük vagy sem - ez egy bónusz:
SELECT * FROM movies LEFT JOIN directors ON directors.id = movies.director_id; A lekérdezés ugyanazon mintát követi, mint korábban - a csatlakozást éppen a-ként adtuk meg LEFT JOIN.
In this example, the movies table is the "left" table.
If we write the query on one line it makes this a little easier to see:
... FROM movies LEFT JOIN directors ... A left join returns all records from the "left" table.
A left join returns any rows from the "right" table that match the join condition.
Rows from the "right" table that don't match the join condition are returned as NULL.
id | name | director_id | id | name ----+---------+-------------+------+------------ 1 | Movie 1 | 1 | 1 | John Smith 2 | Movie 2 | 1 | 1 | John Smith 3 | Movie 3 | 2 | 2 | Jane Doe 4 | Movie 4 | NULL | NULL | NULL 5 | Movie 5 | NULL | NULL | NULL (5 rows) Looking at that result set, we can see why this type of join is useful for "all of this and, if it exists, some of that" type queries.
RIGHT JOIN
The RIGHT JOIN works exactly like the LEFT JOIN—except the rules about the two tables are reversed.
In a right join, all of the rows from the "right" table are returned. The "left" table is conditionally returned based on the join condition.
Let's use the same query as above but substitute LEFT JOIN for RIGHT JOIN:
SELECT * FROM movies RIGHT JOIN directors ON directors.id = movies.director_id; id | name | director_id | id | name ------+---------+-------------+----+-------------- 1 | Movie 1 | 1 | 1 | John Smith 2 | Movie 2 | 1 | 1 | John Smith 3 | Movie 3 | 2 | 2 | Jane Doe NULL | NULL | NULL | 5 | Bree Jensen NULL | NULL | NULL | 4 | Bev Scott NULL | NULL | NULL | 3 | Xavier Wills (6 rows) Our result set now returns every directors row and, if it exists, the movies data.
All we've done is switch which table we're considering the "primary" one—the table we want to see all of the data from regardless of if its associated data exists.
LEFT JOIN / RIGHT JOIN in production applications
In a production application, I only ever use LEFT JOIN and I never use RIGHT JOIN.
I do this because, in my opinion, a LEFT JOIN makes the query easier to read and understand.
When I'm writing queries I like to think of starting with a "base" result set, say all movies, and then bring in (or subtract out) groups of things from that base.
Because I like to start with a base, the LEFT JOIN fits this line of thinking. I want all of the rows from my base table (the "left" table), and I conditionally want the rows from the "right" table.
In practice, I don't think I've ever even seen a RIGHT JOIN in a production application. There's nothing wrong with a RIGHT JOIN—I just think it makes the query more difficult to understand.
Re-writing RIGHT JOIN
If we wanted to flip our scenario above and instead return all directors and conditionally their movies, we can easily re-write the RIGHT JOIN into a LEFT JOIN.
Csak annyit kell tennünk, hogy megfordítjuk a lekérdezés tábláinak sorrendjét, és átváltunk RIGHTa következőre LEFT:
SELECT * FROM directors LEFT JOIN movies ON movies.director_id = directors.id; movies) először a csatlakozási feltételbe (
ON movies.director_id = ...) tenni - de ez csak az én személyes preferenciám.
Szűrés a következővel: LEFT JOIN
Két felhasználási eset van egy LEFT JOIN(vagy RIGHT JOIN) használatához.
Az első felhasználási eset, amelyet már lefedtünk: az összes sor visszaküldése az egyik táblázatból, és feltételesen a másikból.
A második felhasználási eset az első tábla sorainak visszaadása, ahol a második táblázat adatai nincsenek megadva.
A forgatókönyv így nézne ki: keressen olyan rendezőket, akik nem tartoznak egy filmhez.
To do this we'll start with a LEFT JOIN and our directors table will be the primary or "left" table:
SELECT * FROM directors LEFT JOIN movies ON movies.director_id = directors.id; For a director that doesn't belong to a movie, the columns from the movies table are NULL:
id | name | id | name | director_id ----+--------------+------+---------+------------- 1 | John Smith | 1 | Movie 1 | 1 1 | John Smith | 2 | Movie 2 | 1 2 | Jane Doe | 3 | Movie 3 | 2 5 | Bree Jensen | NULL | NULL | NULL 4 | Bev Scott | NULL | NULL | NULL 3 | Xavier Wills | NULL | NULL | NULL (6 rows) In our example, director ID 3, 4, and 5 don't belong to a movie.
To filter our result set just to these rows, we can add a WHERE clause to only return rows where the movie data is NULL:
SELECT * FROM directors LEFT JOIN movies ON movies.director_id = directors.id WHERE movies.id IS NULL; id | name | id | name | director_id ----+--------------+------+------+------------- 5 | Bree Jensen | NULL | NULL | NULL 4 | Bev Scott | NULL | NULL | NULL 3 | Xavier Wills | NULL | NULL | NULL (3 rows) And there are our three movie-less directors!
It's common to use the id column of the table to filter against (WHERE movies.id IS NULL), but all columns from the movies table are NULL—so any of them would work.
(Since we know that all the columns from the movies table will be NULL, in the query above we could just write SELECT directors.* instead of SELECT * to just return all of the director's information.)
Using LEFT JOIN to find matches
In our previous query we found directors that didn't belong to movies.
Using our same structure, we could find directors that do belong to movies by changing our WHERE condition to look for rows where the movie data is notNULL:
SELECT * FROM directors LEFT JOIN movies ON movies.director_id = directors.id WHERE movies.id IS NOT NULL; id | name | id | name | director_id ----+------------+----+---------+------------- 1 | John Smith | 1 | Movie 1 | 1 1 | John Smith | 2 | Movie 2 | 1 2 | Jane Doe | 3 | Movie 3 | 2 (3 rows) This may seem handy, but we've actually just re-implemented INNER JOIN!
Multiple joins
We've seen how to join two tables together, but what about multiple joins in a row?
It's actually quite simple, but to illustrate this we need a third table: tickets.
This table will represent tickets sold for a movie:
CREATE TABLE tickets( id SERIAL PRIMARY KEY, movie_id INTEGER REFERENCES movies NOT NULL ); INSERT INTO tickets(movie_id) VALUES (1), (1), (3); The tickets table just has an id and a reference to the movie: movie_id.
We've also inserted two tickets sold for movie ID 1, and one ticket sold for movie ID 3.
Now, let's join directors to movies—and then movies to tickets!
SELECT * FROM directors INNER JOIN movies ON movies.director_id = directors.id INNER JOIN tickets ON tickets.movie_id = movies.id; Since these are inner joins, the order in which we write the joins doesn't matter. We could have started with tickets, then joined on movies, and then joined on directors.
It again comes down to what you're trying to query and what makes the query the most understandable.
In our result set, we'll notice that we've further narrowed down the rows that are returned:
id | name | id | name | director_id | id | movie_id ----+------------+----+---------+-------------+----+---------- 1 | John Smith | 1 | Movie 1 | 1 | 1 | 1 1 | John Smith | 1 | Movie 1 | 1 | 2 | 1 2 | Jane Doe | 3 | Movie 3 | 2 | 3 | 3 (3 rows) This makes sense because we've added another INNER JOIN. In effect this adds another "AND" condition to our query.
Our query essentially says: "return all directors that belong to movies that also have ticket sales."
If instead we wanted to find directors that belong to movies that may not have ticket sales yet, we could substitute our last INNER JOIN for a LEFT JOIN:
SELECT * FROM directors JOIN movies ON movies.director_id = directors.id LEFT JOIN tickets ON tickets.movie_id = movies.id; We can see that Movie 2 is now back in the result set:
id | name | id | name | director_id | id | movie_id ----+------------+----+---------+-------------+------+---------- 1 | John Smith | 1 | Movie 1 | 1 | 1 | 1 1 | John Smith | 1 | Movie 1 | 1 | 2 | 1 2 | Jane Doe | 3 | Movie 3 | 2 | 3 | 3 1 | John Smith | 2 | Movie 2 | 1 | NULL | NULL (4 rows) This movie didn't have any ticket sales, so it was previously excluded from the result set due to the INNER JOIN.
I'll leave this an Exercise For The Reader™, but how would you find directors that belong to movies that don't have any ticket sales?
Join execution order
In the end, we don't really care in what order the joins are executed.
One of the key differences between SQL and other modern programming languages is that SQL is a declarative language.
This means that we specify the outcome we want, but we don't specify the execution details—those details are left up to the database query planner. We specify the joins we want and the conditions on them and the query planner handles the rest.
But, in reality, the database is not joining three tables together at the same time. Instead, it will likely join the first two tables together into one intermediary result, and then join that intermediary result set to the third table.
(Note: This is a somewhat simplified explanation.)
So, as we're working with multiple joins in queries we can just think of them as a series of joins between two tables—although one of those tables can get quite large.
Joins with extra conditions
The last topic we'll cover is a join with extra conditions.
Similar to a WHERE clause, we can add as many conditions as we want to our join conditions.
For example, if we wanted to find movies with directors that are notnamed"John Smith", we could add that extra condition to our join with an AND:
SELECT * FROM movies INNER JOIN directors ON directors.id = movies.director_id AND directors.name 'John Smith';We can use any operators we would put in a WHERE clause in this join condition.
We also get the same result from this query if we put the condition in a WHERE clause instead:
SELECT * FROM movies INNER JOIN directors ON directors.id = movies.director_id WHERE directors.name 'John Smith';There are some subtle differences happening under the hood here, but for the purpose of this article the result set is the same.
(If you're unfamiliar with all of the ways you can filter a SQL query, check out the previously mentioned article here.)
The reality about writing queries with joins
In reality, I find myself only using joins in three different ways:
INNER JOIN
The first use case is records where the relationship between two tables does exist. This is fulfilled by the INNER JOIN.
These are situations like finding "movies that have directors" or "users with posts".
LEFT JOIN
The second use case is records from one table—and if the relationship exists—records from a second table. This is fulfilled by the LEFT JOIN.
These are situations like "movies with directors if they have one" or "users with posts if they have some."
LEFT JOIN exclusion
The third most common use case is our second use case for a LEFT JOIN: finding records in one table thatdon'thave a relationship in the second table.
These are situations like "movies without directors" or "users without posts."
Two very useful join types
I don't think I've ever used a FULL OUTER JOIN or a RIGHT JOIN in a production application. The use case just doesn't come up often enough or the query can be written in a clearer way (in the case of RIGHT JOIN).
I have occasionally used a CROSS JOIN for things like spreading records across a date range (like we looked at the beginning), but that scenario also doesn't come up too often.
So, good news! There's really only two types of joins you need to understand for 99.9% of the use cases you'll come across: INNER JOIN and LEFT JOIN!
If you liked this post, you can follow me on twitter where I talk about database things and all other topics related to development.
Thanks for reading!
John
P.S. an extra tip for reading to the end: most database systems will let you just write JOIN in the place of INNER JOIN—it'll save you a little extra typing. :)